Matematika Sekolah Menengah Pertama 1. (2× 4)³ =
2.(2³)² =
3.(4 × 5)² =
4.6²)⁴ =​

1. (2× 4)³ =
2.(2³)² =
3.(4 × 5)² =
4.6²)⁴ =​

Penjelasan dengan langkah-langkah:

1)

(2 × 4)³

8 × 8 × 8

8 × 64

512

2)

(2³)²

2^(3 × 2)

2⁶

64

3)

(4 × 5)²

20²

20 × 20

400

4)

(6²)⁴

6^2 × 4

6⁸

Jawaban:

1. (2 × 4)³

= 2³ × 4³

= 8 × 64

= 512

2. (2³)²

Memakai rumus : (a^m)^n = a^m × ^n

(2³)² = 2³ × ² = 2^6 = 64

3. (4 × 5)²

= 4² × 5²

= 16 × 25

= 400

4. (6²)⁴

Memakai rumus : (a^m)^n = a^m × ^n

(6²)⁴ = 6² × ⁴ = 6^8

Semoga membantu !

Detail Jawaban :

Materi : Bab 1 Perpangkatan dan bentuk akar

Kelas : IX

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